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30y^2+70y=0
a = 30; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·30·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*30}=\frac{-140}{60} =-2+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*30}=\frac{0}{60} =0 $
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